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Area = length x width Perimeter = length + width Therefore, an example would best be suited here. Area = 5 x 6 = 30 Perimeter = 5 + 6 = 11 (Just using random variables to support their hypothesis)
So it would be 11 or was that part of the example? (sorta confused) @_Squish
@_Squish
We're just testing their hypothesis to see which one is in fact correct. To say that two items need the same perimeter to have the same area cannot be possible. My best bet would be for D, but I would need to do some serious variable plugging to confirm their hypothesis.
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Oh... Thank you for clearing that up....
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