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Geometry 15 Online
OpenStudy (anonymous):

Check these questions please. c: @Michele_Laino

OpenStudy (anonymous):

OpenStudy (michele_laino):

question #1 the base of the rectangle is: \[base = \sqrt {{{\left( {7 - 1} \right)}^2} + {{\left( {3 - \left( { - 3} \right)} \right)}^2}} = \sqrt {36 + 36} = 6\sqrt 2 \] whereas the height of the rectangle, is: \[height = \sqrt {{{\left( {7 - 5} \right)}^2} + {{\left( {3 - 5} \right)}^2}} = \sqrt {4 + 4} = 2\sqrt 2 \] |dw:1429565858774:dw|

OpenStudy (michele_laino):

so, area is: \[area = 6\sqrt 2 \times 2\sqrt 2 = ...?\]

OpenStudy (michele_laino):

for example, the base is the distance between the points (1,-3) and (7,3). So I have applied this formula: \[d = \sqrt {{{\left( {{x_2} - {x_1}} \right)}^2} + {{\left( {{y_2} - {y_1}} \right)}^2}} \]

OpenStudy (anonymous):

24

OpenStudy (michele_laino):

ok!

OpenStudy (anonymous):

So the answer to the first question is 24?

OpenStudy (michele_laino):

yes!

OpenStudy (anonymous):

So are 3 and 4 right?

OpenStudy (michele_laino):

second question: here the requested area, is equal to the area of the rectangle FWCS plus the area of the triangle FSN

OpenStudy (michele_laino):

area of the rectangle FWCS = 9*2=...?

OpenStudy (anonymous):

18?

OpenStudy (michele_laino):

ok!

OpenStudy (michele_laino):

now the area of the triangle is: area = base *height/2=9*6/2=...? since the height is 6 units, or 6 little squares

OpenStudy (michele_laino):

|dw:1429566541948:dw|

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