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Mathematics 22 Online
OpenStudy (anonymous):

There are three monomials such that the greatest common factor of the first and second monomials is 2xy, and the greatest common factor of the second and third monomials is 2x2y. The greatest common factor of the three monomials is......?

OpenStudy (anonymous):

@freckles @amistre64

OpenStudy (amistre64):

set up the information, what do we notice?

OpenStudy (anonymous):

Is 2xy the greatest common factor to both?

OpenStudy (anonymous):

@amistre64 @amistre64

OpenStudy (amistre64):

are we guessing or can we make an arguement for ir?

OpenStudy (amistre64):

** it

OpenStudy (anonymous):

I honestly think so, what about you? I calculated and got this.

OpenStudy (amistre64):

let: m1 = 2xy a m2 = 2xy b m3 = 2x2y c since 2 and 3 have a common factor let b=2n m1 = 2xy a m2 = 2xy 2 n m3 = 2x2y c or simply m1 = 2xy a m2 = 2xy 2n m3 = 2xy 2c given that anc have no common factors

OpenStudy (anonymous):

OK.

OpenStudy (anonymous):

So I was right, thanks @amistre64

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