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Mathematics 9 Online
OpenStudy (saylilbaby):

I chose C Medal

OpenStudy (saylilbaby):

OpenStudy (mahmood786123):

One sec

OpenStudy (mahmood786123):

I'm in 6th grade I got confused looking at the first option

OpenStudy (saylilbaby):

@Michele_Laino

OpenStudy (saylilbaby):

@dan815

jimthompson5910 (jim_thompson5910):

the graph is cut off

jimthompson5910 (jim_thompson5910):

oh nvm, i figured it out

OpenStudy (saylilbaby):

no its not @jim_thompson5910

jimthompson5910 (jim_thompson5910):

have a look at this page http://www.mathwords.com/f/focus_parabola.htm what is the first formula given on there

OpenStudy (saylilbaby):

4p(y-k)=(x-h)^2 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

that's the formula we will use

jimthompson5910 (jim_thompson5910):

what is the vertex of your given graph

OpenStudy (saylilbaby):

v=1,-4 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

so (h,k) = (1,-4)

jimthompson5910 (jim_thompson5910):

how far is the vertex from the focus?

OpenStudy (saylilbaby):

B @Michele_Laino ??

OpenStudy (michele_laino):

I think that @jim_thompson5910 is right, since we have to perform this traslation: \[\left\{ \begin{gathered} x = X + 1 \hfill \\ y = Y - 4 \hfill \\ \end{gathered} \right.\] where X, and Y are the new coordinates

OpenStudy (saylilbaby):

ok when i sub them in what i do next @Michele_Laino

OpenStudy (michele_laino):

using that new coordinates, the equation of our parabola is: Y=k*X^2 now we have to determine what is k

OpenStudy (michele_laino):

if I rewrite that equation, using the old coordinates, I have: \[\Large y + 4 = k{\left( {x - 1} \right)^2}\]

OpenStudy (michele_laino):

so what is the right option?

OpenStudy (michele_laino):

from the data of your graph, we have that the equation of the directrix is: y=-6 furthermore, the equation of the directrix of our parabola: Y=kX^2, is Y=-1/k=-2, so K=1/2 since if we substitute y=-6, into my trasformation above, I get: -6=Y-4, namely Y=-2 so the right option is the first option. @Saylilbaby

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