I chose C Medal
One sec
I'm in 6th grade I got confused looking at the first option
@Michele_Laino
@dan815
the graph is cut off
oh nvm, i figured it out
no its not @jim_thompson5910
have a look at this page http://www.mathwords.com/f/focus_parabola.htm what is the first formula given on there
4p(y-k)=(x-h)^2 @jim_thompson5910
that's the formula we will use
what is the vertex of your given graph
v=1,-4 @jim_thompson5910
so (h,k) = (1,-4)
how far is the vertex from the focus?
B @Michele_Laino ??
I think that @jim_thompson5910 is right, since we have to perform this traslation: \[\left\{ \begin{gathered} x = X + 1 \hfill \\ y = Y - 4 \hfill \\ \end{gathered} \right.\] where X, and Y are the new coordinates
ok when i sub them in what i do next @Michele_Laino
using that new coordinates, the equation of our parabola is: Y=k*X^2 now we have to determine what is k
if I rewrite that equation, using the old coordinates, I have: \[\Large y + 4 = k{\left( {x - 1} \right)^2}\]
so what is the right option?
from the data of your graph, we have that the equation of the directrix is: y=-6 furthermore, the equation of the directrix of our parabola: Y=kX^2, is Y=-1/k=-2, so K=1/2 since if we substitute y=-6, into my trasformation above, I get: -6=Y-4, namely Y=-2 so the right option is the first option. @Saylilbaby
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