If a square that measures 11 feet on a side it attached to a rectangle that measures 9 feet by 11 feet, what is the total area of the attached shaped?

Question

anonymous · Answer

@TheSmartOne  can u help me please?

thesmartone · Answer

Find the area of the square, and ad it to the area of the rectangle.

$\sf\Large Area~ of ~a ~square = side^2$

$\sf\Large Area~ of~ a~ rectangle =~= Length \times width$

thesmartone · Answer

add it to the*

anonymous · Answer

is the are 40?

thesmartone · Answer

umm not even close

$\sf 9^2 + 9 \times 11=?$

anonymous · Answer

180

thesmartone · Answer

Correct.

anonymous · Answer

how what about the area of the rectangle?

thesmartone · Answer

that was the $\sf 9\times11$

anonymous · Answer

okay so what would I do next?

thesmartone · Answer

That is all.

You found the area of the square which is $\sf 9^2$
And the area of the rectangle which is $\sf 9\times11$

And then you added them together and got 180. c:

anonymous · Answer

220 square feet would be the answer in my answer book.

anonymous · Answer

9*11+11*11=220

thesmartone · Answer

oops, I accidentally switched the numbers.

11 is the side of the square. So it would ne $\sf 11^2 + 9\times 11$

anonymous · Answer

its okay! thanks @TheSmartOne  and @robtobey

thesmartone · Answer

(:

anonymous · Answer

11^2 = 121, 9 * 11 = 99, 121 + 99 = 220