Question

Help..
How do you solve trignometric equations where the ratio is negative. For example tan x = -sqrt(3)

Answer 1

If \(\tan x = -\sqrt{3}\)
you can be sure that x is in the second or the fourth quadrant.

If tan x = -sqrt{3}

x = tan^-1 (-sqrt{3}) = - tan^-1 (sqrt{3}) = - pi/3

Answer 2

Do you know inverses trigonometric functions?

Answer 3

check it counter clock wise

Answer 4

no.. we haven't done inverses yet

Answer 5

sorry for the late response