Question

Please help? iv got no idea of to solve this.

Answer 1

Ok so first find the equation of the line do you know how to do this?

Answer 2

not at all. :c

Answer 3

Ok so the equation of a line is y = mx + b where m is the slope and b is the y intercept. Looking at your answers forget about the less then or greater then sign for now. take a look at the 9x. The options state either -9x or 9x in all four. Now take a look at the line. Do two things. Find where it crosses the y-axis and then look to see if the slope is negative or positive. This is done by using rise over run so picking a point on the line either go up or down and then go left or right to another point on the line. Up is positive down is negative and left is negative and right is positive. so if you have to go up then left its positive over negative giving you a negative slope if you have to go up then right then its positive over positve giving you a positive slope. If you have to go down then right its negative over positive giving you a negative slope. If you have to go down then left its negative over negative giving you a positive slope.

Answer 4

So what values do you have for the line crossing the y-axis and did you find the slope to be negative or positive?

Answer 5

4, and Negative?

Answer 6

@Rhystic ?

Answer 7

5 and negative

Answer 8

if you look at the picture it just crosses a bit above 4 but below 6

Answer 9

oh okay i see

Answer 10

oh wait

Answer 11

Ok so now bring all of the equations to a positive y < form so the first one would be -9x+5>y. do this for the rest of them

Answer 12

After you do find which ones have a negative slope and a positive y. Then you have to worry about the > < signs.

If the shaded part is above the line then you need a y > sign. If the shaded part is below the line then you need a y < sign.

Answer 13

after you have done that what answer do you come up with?

Answer 14

Are you still working the problem?

Answer 15

yes i am, i have no idea how to do what you said

Answer 16

@Rhystic

Answer 17

ok so for instance the first answer is -9x - y > -5 . You need to bring it into a positive y =/>/< form so it becomes -9x - y > -5 -> -9x > y -5 -> -9x + 5 > y or y < -9x + 5. You need to do this for all the other answers, and then look for positive 5 and a negative slope (-9x) and a y > sign because the shaded porition is above the line. If the shaded portion was below the line then you would have y <. Does that make sense?

Answer 18

i guess it makes sense, but idk how to bring then into positives

Answer 19

it sucks cuz iv already taken this test once, and now all the questions are completely different.

Answer 20

basically your just bringing the numbers to one side of the equation or the other.
so if you had : 9x + y > 5 and you wanted positive y alone on the side you would subtract 9x from both sides leaving you with y > 5-9x.

Answer 21

if you try to do this with the second answer I will let you know if you are correct or not.

Answer 22

is the answer A?

Answer 23

no the answer is not A. Do what I asked you to do. It will make the rest of the questions for you easiar.

Answer 24

y > 5 + 9x

Answer 25

?

Answer 26

not quite.

Answer 27

so you have -9x + y < -5 you already have a positive y so you just need to bring the 9x over. so add 9x to both sides making 9x - 9x + y < -5 + 9x which makes y < -5 + 9x

Answer 28

make sense?

Answer 29

i guess

Answer 30

so then what is the answer?

Answer 31

Do it for the third one. I know you just want to get the test done with but you're just screwing yourself over if you don't figure this out.

Answer 32

not really, this is my last test for my segment and im so tired of this and i just want to be done. i want to go back to actual school, and iv already taken this stupid thing and just barely didnt get a high enough grade for it.

Answer 33

y < -5 - 9x ?

Answer 34

explain your steps for me

Answer 35

i dont know, i just kinda did what you said.

Answer 36

why, was it wrong?

Answer 37

yeah.

Answer 38

hang one lemme see if I can draw it step by step

Answer 39

cant you please just tell me. iv been stuck on this one for over an hour and i still have like 40 left to do.

Answer 40

whatever the third one is the answer

Answer 41

thank you.