Question

Well, I'm stumped.
http://prntscr.com/6wkc6z

Answer 1

you can use law of cosines . note that the angle in the middle there is 49.17 + 90

Answer 2

Would angle P (I'm using that for the plane's angle) be 40.83?

Answer 3

http://prntscr.com/6wkfan

Answer 4

I see.

Answer 5

Distance^2 = 150^2 + 170^2 - 2(150)(170) cos( 49.19 + 90)
Distance = sqrt(150^2 + 170^2 - 2(150)(170) cos( 49.19 + 90))

Answer 6

Alright, thank you. I think I understand it now.