Question

@StudyGurl14
@jdoe0001

Answer 1

Ok, could I do this one the same way?

Answer 2

\(\textit{function transformations}
\\ \quad \\

\begin{array}{llll}

\begin{array}{llll} shrink\ or\\ expand\\ by\ {\color{purple}{ A}}\end{array}
\qquad
\begin{array}{llll} vertical\\ shift\\ by \ {\color{green}{ D}} \end{array}

\begin{array}{llll}{\color{green}{ D}} > 0& Upwards\\ {\color{green}{ D}} < 0 & Downwards\end{array}
\\

% template start
\qquad \downarrow\qquad\qquad\quad\ \downarrow\\
y = {\color{purple}{ A}} \sqrt{ x + {\color{red}{ 2}} } + {\color{green}{ D}}\\
%template end
\qquad\qquad \quad \uparrow \\

\qquad\begin{array}{llll} horizontal\\ shift\\ by \ {\color{red}{ C}}\end{array}

\begin{array}{llll}{\color{red}{ C}} > 0 & to\ the\ left\\ {\color{red}{ C}} < 0& to\ the\ right\end{array}
\end{array}\)

Answer 3

should be simple enough

Answer 4

would it switch to negative

Answer 5

f(x) ---> f(x+a) is a transformation of a units to the left

Answer 6

welll. just notice if Cis negative or positive
and take it from there :)

Answer 7

ok I got D

Answer 8

Yep.

Answer 9

plz tell me thats right

Answer 10

yeap, +2 means 2 units to the left