Question

what is the points of discontinuity? Are they all removable? y=(x-5)/x^2-6x+5

Answer 1

\[y = \dfrac{x-5}{x^2-6x+5}\]

Try factor denominator, then set it equal to zero, so you can solve for value of x where y is undefined.

Answer 2

Discontinuity point is removable if you simplify original function and suddenly that point now exists in function.

Answer 3

So when function is completely simplified, any discontinuity points it still have; they are non-removable.

Does that make sense?