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Solve using substitution: y=-x^2+3 Y=3x-7
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Can anyone help me
okie dokie. We know y=3x-7 So since y=x^2+3 then 3x-7=x^2+3 Then make a quadratic equation x^2-3x+10=0
Then use quadratic equation to solve for x, Plugin BOTH x's in BOTH formulas to check if both X value is correct, if one of them or both do not work then negate them
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