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Mathematics 22 Online
OpenStudy (anonymous):

WILL GIVE MEDAL AND FAN PLZ HELP ASAP

OpenStudy (anonymous):

http://www.math-magic.com/geometry/determine_tri.htm

OpenStudy (anonymous):

@amistre64

OpenStudy (anonymous):

someone plz help

rvc (rvc):

which trigonometric ratio would you use?

rvc (rvc):

@HWBUSTER00

OpenStudy (anonymous):

what ?? @rvc

OpenStudy (anonymous):

can you help me lol @Race100

geerky42 (geerky42):

That's 45 45 90 triangle, so ratio of hypotenuse to leg is \(\sqrt2\).|dw:1429716517631:dw| And here, we have \(x = 5\sqrt2\), what is \(c = x\sqrt2\)?

OpenStudy (anonymous):

@ikr

geerky42 (geerky42):

What is \(5\sqrt2\cdot\sqrt2\)?

OpenStudy (anonymous):

10

geerky42 (geerky42):

There you go.

OpenStudy (anonymous):

@ikram002p

OpenStudy (anonymous):

the answer is 10

geerky42 (geerky42):

Yes.

geerky42 (geerky42):

\[x\sqrt 2 = 5\sqrt2\sqrt2 = 10 = c\]

OpenStudy (anonymous):

thanks so much ong i have been waiting @gee

OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

I have another one @geerky42 can can you do another one well help me . its very similar

geerky42 (geerky42):

Ok post it.

OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

@bohotness

geerky42 (geerky42):

So to find x, you just divide height by \(\sqrt3\)

OpenStudy (anonymous):

divide what by \[\sqrt{3}\]

OpenStudy (anonymous):

@geerky42

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