Question

f is a differentiable function on the interval [0, 1] and g(x) = f(4x). The table below gives values of f '(x). What is the value of g '(0.1)?

Answer 1

@rational

Answer 2

@amistre64 @dan815 @Godlovesme @inowalst @Preetha @sleepyhead314 @sleepyjess @HelpBlahBlahBlah @JFraser @Mashy @triciaal

Answer 3

Please help!!

Answer 4

@dan815 Do you have any ideas?

Answer 5

@dan815 Do you have any ideas?

Answer 6

@Michele_Laino

Answer 7

If we use the chain rule, we get:
\[\Large g'\left( x \right) = 4f'\left( y \right),\quad y = 4x\]

Answer 8

so we can write:
\[\Large g'\left( {0.1} \right) = 4f'\left( y \right) = 4f'\left( {0.4} \right) = ...?\]