Mathematics
14 Online
OpenStudy (anonymous):
Help me with this problem please?
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OpenStudy (anonymous):
undeadknight26 (undeadknight26):
I has no idea x.x
OpenStudy (anonymous):
;-;
OpenStudy (anonymous):
Okay ill post the last one and get help with this in a sec so you can go sleep
undeadknight26 (undeadknight26):
@amistre64 @dan815 @DarkBlueChocobo @freckles @confluxepic @e.mccormick Can chu help dis luvleh purson?
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OpenStudy (confluxepic):
Th simplest of the simplest. Just plug in the values. @AllyBearxx
OpenStudy (anonymous):
How would i do that?
OpenStudy (confluxepic):
\(\huge\ f(x)=9x+7\)
OpenStudy (confluxepic):
On the side it shows the values of x.
OpenStudy (confluxepic):
\(\huge\ f(-2)=9(-2)+7\)
\(\huge\ 9(-2)+7=-11.\)
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OpenStudy (confluxepic):
\(\huge\ f(0)=9(0)+7=?\)
OpenStudy (anonymous):
16?
OpenStudy (confluxepic):
Anything multiplied with 0 would become 0.
OpenStudy (anonymous):
ohk
OpenStudy (confluxepic):
So 0+7=?
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OpenStudy (anonymous):
7
OpenStudy (confluxepic):
Yes.
OpenStudy (confluxepic):
Then fill in that value in that chart.
OpenStudy (anonymous):
thats where i was trying to put it, thank you i just couldnt figure out how cx
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OpenStudy (anonymous):
so then the next one?
OpenStudy (confluxepic):
\(\huge\ f(1)=9(1)+7=?\)
OpenStudy (anonymous):
that one is 16 cx
OpenStudy (anonymous):
right? @confluxepic
OpenStudy (confluxepic):
Yes.
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OpenStudy (anonymous):
okk, could you add that to the chart for me? im unable to xc
OpenStudy (anonymous):
Awesome, so the next one?
OpenStudy (confluxepic):
\(\huge\ f(2)=9(2)+7=?\)
OpenStudy (anonymous):
25?
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OpenStudy (confluxepic):
Yes.
OpenStudy (anonymous):
okay i added it this time using the website you did, next one?
OpenStudy (confluxepic):
\(\huge\ g(x)=5^x=?\)
OpenStudy (anonymous):
that one looks different than the others, how do i solve that?
OpenStudy (confluxepic):
\(\huge\ g(-2)=5^{-2}=?\)
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OpenStudy (anonymous):
oh, -10?
OpenStudy (anonymous):
and then the next one is -5?
OpenStudy (confluxepic):
No.
OpenStudy (confluxepic):
Lets do this one first.
\(\huge\ g(2)=5^{2}=?\)
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OpenStudy (confluxepic):
Lets do this one first.
\(\huge\ 5^{2}=5\times 5=?\)
OpenStudy (anonymous):
?
OpenStudy (anonymous):
5x5 is 25
OpenStudy (anonymous):
ohhhh to the power of
OpenStudy (confluxepic):
Yes.
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OpenStudy (anonymous):
so it would be 5 ÷ 5?
OpenStudy (confluxepic):
25 was correct.
OpenStudy (anonymous):
positive or negative?
cuz its a negative exponent
OpenStudy (anonymous):
so then what is the equation for the next one?
OpenStudy (confluxepic):
I made it 5 to the power of 2.
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OpenStudy (confluxepic):
Which would be 25.
OpenStudy (anonymous):
so thats the answer for that one?
OpenStudy (anonymous):
ooh gotcha
OpenStudy (anonymous):
so what about the first 2 for that column?
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OpenStudy (confluxepic):
If you look at the question you can tell that we don't have to do those. You already got your answer.
OpenStudy (anonymous):
oh i did?
OpenStudy (confluxepic):
Where did the 25's appear twice?
OpenStudy (anonymous):
wait so is it 2, or 25?
OpenStudy (anonymous):
cuz it appeared with 2x, but then they were both 25's so im confused on that
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OpenStudy (confluxepic):
They would both equal 25 only when x=2.
OpenStudy (anonymous):
okay so its c :D
OpenStudy (confluxepic):
Yes.
OpenStudy (anonymous):
thanks so much c: