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3 log 2x=4
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divide by \(3\) first and start with \[\log_2(x)=\frac{4}{3}\]
oh before we begin, lets make sure is it \[3\log_2(x)=4\]?
hey satellite i need help with my problem please when u have time
No no it does not give a base of 2 . It is just 3 log 2x=4
oh \[3\log(2x)=4\]
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so \[\log(2x)=\frac{4}{3}\] without a base it is assumed to be ten, so in equivalent exponential form this is \[2x=10^{\frac{4}{3}}\]
so \[x=\frac{10^{\frac{4}{3}}}{2}\] whatever that is
hahaha alright! yeah! that makes sense
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