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Mathematics 17 Online
OpenStudy (anonymous):

graphing trig functions. please help

OpenStudy (johnp12):

what is it?

OpenStudy (anonymous):

i have to put the equation onto a graph and find the amplitude,period,vertical shift,domain and range and the start point

OpenStudy (anonymous):

@johnp12

OpenStudy (johnp12):

oh um im not to sure

OpenStudy (anonymous):

if you didnt know why did you ask lol @johnp12

OpenStudy (freckles):

well can you say what the equation is and we can go from there?

OpenStudy (freckles):

y=a*sin(b(x-c))+d |a| is amp c is phase shift 2pi/b is period d is vertical shift

OpenStudy (anonymous):

y=1+4cos theta i have to graph it

OpenStudy (freckles):

cos and sin have the same above information y=4cos(x)+1 can you identify the amp number?

OpenStudy (anonymous):

4

OpenStudy (freckles):

right! and the phase shift doesn't change from its parent graph since we just have cos(x) you can say the phase shift is 0 though since you can write y=4cos(1(x-0))+1

OpenStudy (freckles):

the period is also the same as its parent graph since 2pi/1=2pi can you identify the vertical shift?

OpenStudy (anonymous):

wouldnt it be theta

OpenStudy (freckles):

no remember the vertical shift in y=a*cos(b(x-c))+d is d so the vertical shift in y=4cos(x)+1 is?

OpenStudy (anonymous):

so if there is theta you would put 1 in for it?

OpenStudy (freckles):

if you are saying the vertical shift is 1 you are right I don't know why we are talking about the variable inside the cosine function.

OpenStudy (anonymous):

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