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Mathematics 21 Online
OpenStudy (anonymous):

A spinner numbered 1 through 5 is spun 3 times. What is the probability of spinning a number less than 3 each time? Are these events dependent or independent? (Points : 1) Option A: 8/125; dependent Option B: 1/15; independent Option C:8/125 ; independent Option D: 1/15; dependent

OpenStudy (anonymous):

What are the odds of being below 3? Does the previous spin impact the next spin?

OpenStudy (anonymous):

One spin does not impact the other, so it is independent. The odds of spionning below 3 is 60% or 0.6

OpenStudy (anonymous):

To find the odds of doing it more than once, multiply it by itself. (you raise it to the power of the amount of trials)

OpenStudy (welshfella):

odds of spinning number below 3 is 40%

OpenStudy (welshfella):

or 2/5

OpenStudy (anonymous):

So the odds are (.4)(.4)(.4) or .4^3= .064 To find the percent multiply by 100. It is a 6.4% to spin below 3 3 times.

OpenStudy (welshfella):

for 3 throws it is 2/5 * 2/5 * 2/5

OpenStudy (anonymous):

...

OpenStudy (anonymous):

It is 6.4%

OpenStudy (welshfella):

yes 6.4% or 8/125 as a fraction

OpenStudy (anonymous):

Am I allowed to be confused? hahaha

OpenStudy (welshfella):

dont be confused the 2 answers are correct Phil worked it out in decimals and i worked it out in fractions

OpenStudy (welshfella):

option C is correct

OpenStudy (anonymous):

okay fractions look less intimidating Thank you!! Again... :O xD

OpenStudy (welshfella):

yw

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