Can someone explain how I need to work this?
Quadrilateral OPQR is inscribed in circle N, as shown below. What is the measure of ∠QRO? Quadrilateral OPQR is inscribed in circle N. Angle O is labeled x plus 17 degrees, angle Q is 6x minus 5 degrees, and angle R is 2x plus 19 degrees. 41 67 113 139
all angles add up to 360
opposing angles add up to 180
|dw:1429920735382:dw|
by some thrm i cant think of the name for: and angle is half the measure of its subtend arc arc(ABC) + arc(CDA) = 360 ang(B) = arc(CDA)/2 ang(D) = arc(ABC)/2 ang(B) + ang(D) = [arc(ABC) + arc(CDA)]\2 ang(B) + ang(D) = 360\2 = 180
so can you find x now?
For x, I got 16.5 repeating, but I don't think that's right.
O + Q = 180 x+17 + 6x-5 = 180 7x+12 = 180 7x = 168 yeah, your calculations are in error
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