Ask your own question, for FREE!
Algebra 14 Online
OpenStudy (anonymous):

y varies inversely with x, and k (the constant of variation) = 2. What is the value of y when x = 5?

Nnesha (nnesha):

do you know the equation for inverse variation ?

OpenStudy (anonymous):

no

Nnesha (nnesha):

equation for inverse variation \[\huge\rm y = \frac{ k }{ x }\] replace variables by their values then solve for y

OpenStudy (anonymous):

so i have to divide

Nnesha (nnesha):

k divide by x yes

Nnesha (nnesha):

or you can keep it in fraction form it's depends on answer

OpenStudy (anonymous):

is it 1.4

Nnesha (nnesha):

nope....

OpenStudy (anonymous):

oh sorry i divided the wrong problem lol

OpenStudy (anonymous):

0.4

Nnesha (nnesha):

yes!

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

can you please give me the formula for this problem y varies inversely with x, and k (the constant of variation) = 5.6. What is the value of y when x = 4?

Nnesha (nnesha):

key word *inverse* so which equation you suppose to use ??

OpenStudy (anonymous):

the same one?

Nnesha (nnesha):

yes

OpenStudy (anonymous):

thanks, i get confused sometimes with the formulas

OpenStudy (anonymous):

i dont know when to dive or multiply

Nnesha (nnesha):

okay for inverse equation you should divide k by x \[\huge\rm y = \frac{ k }{ x }\] and for *DIRECT* variation you should multiply k by x \[\huge\rm y = kx \]

Nnesha (nnesha):

sometimes they would give u x and y values then it's your responsibility to find k

OpenStudy (anonymous):

ohh thank you so much

Nnesha (nnesha):

my pleasure :-) and \(\huge\color{Green}{{\rm welcome}\rm~to~open~study!!!!}\)\(\Huge \color{gold}{\star^{ \star^{\star:)}}}\Huge \color{green}{\star^{ \star^{\star:)}}}\) \(\Huge \color{blue}{\star^{ \star^{\star:)}}}\Huge \color{red}{\star^{ \star^{\star:)}}}\)\(\rm\color{green}{o^\wedge\_^\wedge o}\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!