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Solve rational equations \frac(9)(x+1)-\frac(5)(2) = \frac(2)(3x+3).
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\[\frac{9}{x+1}-\frac{5}{2} = \frac{2}{3x+3} \]
yea?
yes
btw you were close with the LAtex, you need to use curly brackets instead of parentheses and add a \bracket to both ends
alright, so anyways, what have you tried so far?
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well im confused since theres two x.
i know from 3x+3 its 3(x+1)
that is true
so you have a few ways to go about it
do i multiply by 6(x+1)
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well you could, but you wont really need the 6, it does eliminate all of the fractions though
I mean it is legal and it works
let me know what you get when you do
help me please with number 1
(don't forget to use parentheses so you hit every term!)
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