Consider the line -9x-5y=7 . Find the equation of the line that is perpendicular to this line and passes through the point −3, 2 . Find the equation of the line that is parallel to this line and passes through the point −3, 2 .
it is easier if you convert the original equation into the form y = mx + c can oyu do that first?
-5y=-9x+7
no quite - you need to be careful of the - sign
well can you help me
I am helping - you are nearly there you just made a simple error when you arranged the formula. Have a look again at what oyu did - be careful of the minus sign....
5y=9x-7
no sorry - that is still not correct . slow down a little... -9x-5y=7 first add 9x to each side.... then divide each side by -5
ok i see so -5y=9x+7 = y= -9/5x+7/5
ok that's right now this form tells you about the line it is in th e form y=mx +c the value of m is the slope of the line - what is th eslope in this case?
-9/5
OHH it's still not right you divide by -5 so it's y= -9/5x -7/5 OK? you are correct about the slope tho - it's -9/5
so oyu probably know if the slope of a line is m what is the slope of a perpendicular line?
5/9
good - that's right so now oyu need to find a line with that slope passing through (-3,2)
so plug in the coordinates ??
so oyu know the equation of that line is y = 5/9 x +b and ypou know that when y = 2 then x = -3
okay now i understand
yes plug in those values ot solve for b
2=5/9(-3)+b
-2
ugh i -2=5/9(3)+b
and for the second part the parallel line has the SAME slope as the original , but passes through the point (-3,2) so do the same for that equation
2=-9/5(-3)+b
-2 =-9/5(3)+b
you need to solve for b in both cases
oh
how do i do the fraction again
you wrote this for the first part 2=5/9(-3)+b so 2+(15/9) = b simplify that
b=11/3
its asking for the equation of the line so i dont solve it
correct so the formula is y = mx + b m =5/9, b= 11/3
y=5/9x+11/3
that is correct |dw:1430010514656:dw|
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