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\[\frac{ \ln ey }{ \ln e^2}\]
y is an exponent of e ?? at the numerator ?
yes
ln of e
\[\huge\rm \frac{ \ln e^y }{ \ln e^2}\] like this ?
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no e and y multiply each other as does e and 2
oops sorry in the demominator, it is e^2
\[\huge\rm \frac{ \ln e \times y }{ \ln e^2}\] like this ?
yeas
okay ln and e are inverse of each there so they can cancel each other out for example \[\huge\rm ln e^x = x ~~~~~ \ln e^2 = 2\]
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so would it just be y/2
yep
thanks
np :-)
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