Question

Which of the following functions grows the fastest as x grows without bound?

Answer 1

@acxbox22 @amistre64 @CausticSyndicalist @dan815 @jagr2713 @misty1212 @myininaya @quickstudent @TheSmartOne @triciaal

Answer 2

so without bound means with out limit. I would replace x with infinity and see which one grows quicker

Answer 3

@16shuston so how would i set up on of these examples. idk how to solve it

Answer 4

by elimination it would be A or B
has to be an exponential function
x is approaching infinity very large so fraction is close to zero

Answer 5

cos x is limited

Answer 6

okay so it's e^x then?

Answer 7

yeah that one is growing the quickest

Answer 8

can u guys help me with another problem?

Answer 9

next time open new question

Answer 10

g(x) = f(2x)
function f when x = 0 g (x) = 0
function f when x = 1 g(x) = 2

Answer 11

@triciaal how do i set this up?

Answer 12

@amistre64

Answer 13

youhave a chain rule ...

Answer 14

g = f(2x)

what is g'?

Answer 15

f(2)+2x

Answer 16

thats not the chain rule

define the chain rule for me

Answer 17

g and f are the names of functions, they are not variables ..

this isnt: g = f, times 2x

this is: g composed of x, is equal to f composed of (2x)

g(x) = f(2x) , a function within a function requires the chain rule

Answer 18

@amistre64 chain rule is