Question

the length of a rectangle is 4.8 cm more than 2 times the width. If the perimeter of the rectangle is 52.8 cm, what are its dimensions?

Answer 1

you must come up with an expression that will help you get the answer

Answer 2

ok. The hint i got was P=2l + 2w

Answer 3

I already know p is 52.8

Answer 4

and l=2w+4.8 because your length must be 4.8cm longer than twice your width

Answer 5

do you see how i got that

Answer 6

yes.

Answer 7

52.8= 4w+4.8 ?

Answer 8

i dont think it is necessary to multiply w by 2

Answer 9

u should get the values for w and l before multiplying by 2

Answer 10

ok then 52.8=2w+4.8

Answer 11

yes

Answer 12

w=24 so then add 4.8 and multiply by 2?

Answer 13

let me see

Answer 14

24+4.8 =28.8
28.8 * 2 = 57.6/
so no

Answer 15

i guess i should just subtract 52.8 and 24.

Answer 16

because you could plug in l=2w+4.8 into p=2l+2w
getting you 4w+9.6+2w=52.8

Answer 17

try and see if that works

Answer 18

that should get you the right answer and sorry for the confusion

Answer 19

ok
yea it did thanks.