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Mathematics 10 Online
OpenStudy (vera_ewing):

Check my work for errors.

OpenStudy (vera_ewing):

If 4x + 3y = 18xy and 2x - 5y + 4xy = 0, then what are the values of x and y respectively?

OpenStudy (vera_ewing):

This is what I did please check it: 4x + 3y = 18xy 4x + 3y - 18xy = 0----(1) 2x - 5y + 4xy = 0 -----(2) Multiply (2) by -2, -4x +10y - 8xy = 0------(3) 4x + 3y - 18xy = 0 -----(1) Adding (3) and (1), 13y - 26xy = 0 y(13 - 26x) = 0 Either y = 0 or 13 - 26x = 0. But y cannot be 0, which is clear from (1). Therefore, 13 - 26x = 0, -26x = -13, x=-13/-26 = 1/2 Substituting this value in (1), 4(1/2) + 3y -18(1/2)y = 0 2 + 3y -9y = 0 -6y = -2, y = -2/-6 = 1/3. hence the values of x and y are 1/2 and 1/3 respectively.

OpenStudy (bahrom7893):

This is how you can check your own work: plug both x and y into both equations, and make sure the results are correct

OpenStudy (bahrom7893):

i.e.: is 4 * (1/2) + 3 * (1/3) equal to 18 * (1/2) * (1/3) ?

OpenStudy (bahrom7893):

The numbers have to work for both equations

OpenStudy (vera_ewing):

Can you show me how to do that exactly?

OpenStudy (bahrom7893):

4 * (1/2) + 3 * (1/3) = 18 * (1/2) * (1/3) 2 + 1 = 9 * (1/3) 3 = 3 This equation looks correct, now do the same for the other one

OpenStudy (vera_ewing):

Thanks!

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