Find the nth term of the sequence 1,-4,9,-16,... A) an=32 B) an=-2n C) an=(-2)^n D) an=(-1)^n • (n)^2 E) an=n^2
I need help please . I can't match any of the answers
hint : all the numbers are squares except there is a negative sign in front of the even number squares
- so there is an n^2 involved in the nth term
Ok sorry why is there a negative only on the even numbers ,what formula match the sequence
yes - i was thinking that an was = D but thats not correct
because first term when n = 1 would be (-1)^1 * (1)^2 = -1 * 1 = -1 not 1
None of the options fit the sequence correct an would be (-1)^(n-1) * (n)^2 here a1 = (-1)^0 * (1)^2 = 1*1 = 1 a2 = (-1)^1 * (2)^2 = -1*4 = -1 a3 = (-1)^2 * (3)^2 = 1 * 9 = 9
I know ,so all of them are wrong ?
yes
could there be a typo somewhere?
D is the closest
D would give a sequence -1,4,-9,16
Oh ok ,thank you
yw
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