What is the area of the rectangle? Round to the nearest square inch.

http://static.k12.com/calms_media/media/1579000_1579500/1579373/2/4ac8cba629d8de89098f07b616577fd1aa6b2747/MS_IMC-150126-130912.jpg

i think its 47in2

Question

What is the area of the rectangle? Round to the nearest square inch.

http://static.k12.com/calms_media/media/1579000_1579500/1579373/2/4ac8cba629d8de89098f07b616577fd1aa6b2747/MS_IMC-150126-130912.jpg


i think its 47in2

anonymous · Answer

@iGreen

igreen · Answer

Use the Pythagorean Theorem to find the length.

igreen · Answer

$\sf a^2 + b^2 = c^2$

Plug in what we known:

$\sf a^2 + 5^2 = 8^2$

Simplify 5^2 and 8^2

anonymous · Answer

thankyouuuuu

igreen · Answer

Just solve for 'a' and multiply it by 5(the width) to get the area.

anonymous · Answer

i got 31in2

igreen · Answer

$\sf a = \sqrt{8^2 - 5^2}$

$\sf A_{rea~of~Rectangle} = \sqrt{8^2 - 5^2} \times 5$

anonymous · Answer

i got 31 D:

igreen · Answer

Yep, you got it.

$\sf a = \sqrt{8^2 - 5^2}$

$\sf a = \sqrt{64 - 25}$

$\sf a = \sqrt{39}$

$\sf a \approx 6.24$

$\sf A_{rea~of~Rectangle} \approx 6.24 \times 5 \approx 31$

anonymous · Answer

Ohh, Thankyou very much