Question

I'm stuck. I'm taking Geometry on FLVS and I'm studying for the final exam. I feel pretty confident about most of it except for the part where it asks me to "Complete the Square" to find the center and radius of a circle using a right triangle.

So how do I factor an equation?
Step 1) x^2-4x+y^2-2y=4-->Original
Step 2) (x^2-4x)+(y^2-2y)=4-->Group like terms
Step 3) (x^2-4x+4)+(y^2-2y+1)=4=(4+1)-->Complete quadratics
Step 4) (x^2-4x+4)+(y^2-2y+1)=9-->Simplfiy
Step 5) Answer: (x-2)^2+(y-1)^2=3^2-->Factor quadratics
Step 6) Center-(2,1) Radius-3
This is mine, (x^2-4x+4)=(y^2-2y=1)=9

Answer 1

@iambatman
@Luigi0210
@Nnesha
@bohotness

Answer 2

@Mimi_x3, help plz:)

Answer 3

Step 6 should read:
Step 3) (x^2-4x+4)+(y^2-2y+1)=4+(4+1)-->Complete quadratics
^
plus instead of equal

Answer 4

Your last line does not make sense. Why do you have all those equal signs? There should only be one equal sign.
"This is mine, (x^2-4x+4)=(y^2-2y=1)=9"

Answer 5

are those steps given ?
so you do not understand how to get step 5 as you agree step 4
well look at step 5 and multiply it out you get your step 4
so it is now in circle equation form (x-h)^2 +(y-k)^2=r^2
(h,k) is the centre r^2=9 ....r=3