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Pythagorean Theorem in 3-D help!!!
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@Mehek14
@TheSmartOne @sleepyjess @dmndlife24 @Baby_Bear69
the fundamental relationship is \[HB^2 = HD^2 + DC^2 + CB^2\] so, \[HB = \sqrt{HD^2 + DC^2 + CB^2}\] NB: the letter orders follow the natural (vector) path from H to B but CB = BC and so on as we are only concerned with actual length and solve as you would a "normal" 2-D Pythagoreas problem, but with the extra axis.
Do you still need help, or does what @IrishBoy123 said make sense?
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