Check my Answer!
Which equation would best help solve the following problem?

The height of a triangle is 6 m more than its base. The area of the triangle is 56 m^2. Find the length of the base.

A. $56 = \frac{ 1 }{ 2 }(x)(x + 6)$
B. $56 = \frac{ 1 }{ 2 }( x^2 + 6) $
C. $56 = x(x + 6)$
D. $56 = x^2 + 6$

My answer: A. or B.

Question

Check my Answer!
Which equation would best help solve the following problem?

The height of a triangle is 6 m more than its base. The area of the triangle is 56 m^2. Find the length of the base.

A. $56 = \frac{ 1 }{ 2 }(x)(x + 6)$
B. $56 = \frac{ 1 }{ 2 }( x^2 + 6) $
C. $56 = x(x + 6)$
D. $56 = x^2 + 6$

My answer: A. or B.

vera_ewing · Answer

A = (1/2)bh = 56m^2
bh = 112
b(b+6m) = 112m^2
b^2 + 6b - 112 = 0
(b + 14)(b-8) = 0, b = 8m
(tossing out negative solution)

anonymous · Answer

Sorry for taking so long, I had to type out the answer choices. @vera_ewing