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Given sin theta=\[2\sqrt{10}/7\] and pie/2 is less than theta is less than pie. find cos(theta/2)
answer choices...
a ) \[-2\sqrt{14}/7\] b) \[2\sqrt{14}/7\] c) \[\sqrt{14}/7\] d) none of the above
@acxbox22 think you can help?
@ganeshie8
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sorry i am not good with trignometry :(
@zepdrix @iambatman
use half angle formulas, since \(x\) is in second quadrant, \(\frac{x}{2}\) will be in first quadrant and thus positive : \[\cos(\frac{x}{2})=\sqrt{\dfrac{1+\cos(x)}{2}}\]
find the value of \(\cos(x)\) and plug it in above
how would I find that? :/
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draw a triangle based on given info : \(\sin(x) = \dfrac{2\sqrt{10}}{7}\)
|dw:1430196272552:dw|
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