Micaela and Aliyah are selling cheesecakes for a school fundraiser. Customers can buy pecan cheesecakes and chocolate marble cheesecakes. Micaela sold 8 pecan cheesecakes and 10 chocolate marble cheesecakes for a total of $240. Aliyah sold 10 pecan cheesecakes and 8 chocolate marble cheesecakes for a total of $212. Find the cost of one pecan cheesecake and one chocolate marble cheesecake.
8x+10y=240 10x+7y=212 @phi
you can simplify the first equation
4x+5y=120
ok, now you have 4x+5y=120 10x+7y=212 what's a "least common denominator" of 4 and 10 ?
is it 2?
you can practice that later. but 4*5 is 20 and 2*10 is 20
the idea is to make the number in front of the x the same in both equations (I picked x because the numbers look a tiny bit simpler than for y)
ok so does that make the number infront of x 20?
if you multiply the top equation by 5 and the bottom by 2 can you do that ?
20x+25y=600 and 20x+14y=424
ok, btw, the problem says Aliyah sold 10 pecan cheesecakes and 8 chocolate marble cheesecakes for a total of $212 but you are using 10x+7y=212 ??
oh god, I keep hitting the wrong key hahaha I meant 8!!
I wrote it like that too, jeez I must be slow today
let me fix this then okay. so 20x+16y=424 then
ok. now you have 20x+25y=600 20x+16y=424 any ideas?
do you subtract the bottom equation from the top?
either way, but it's slightly nicer to subtract the bottom from the top
ok so the 20x-20x cancels out and then 25y-16y=9 and 600-424=176
25y-16y=9 not just 9. it is 9y
yes 9y=176
176 divided by 9? right? 19.555556 it says
we are going to get an fraction or decimal in the answer. (It was nicer if we could use 7 instead of 8)
haha true
so y=19.5 and x=5.625?
x and y are dollars and cents
ok but that's right?
If you don't use fractions when solving for x then you should use y with as many decimals as your calculator allows (do not round)
well it was 19.5555556 and 5.625 I'm pretty sure
you should get x= 50/9 = 5.5555...
ahhh I must've just clicked something wrong.
and at the end, round to the nearest cent: 19.56 and 5.56
ok that makes sense. thank you so much :) I just have one question left that I've started. I'll make a new post
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