A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Sheila scoops out a bowl full of nuts and counts how many of each type she has: 17 peanuts, 9 cashews, 12 almonds, and 10 walnuts.

Armando scoops out a bowl of 32 nuts. About how many should he expect to be cashews?

Question

A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Sheila scoops out a bowl full of nuts and counts how many of each type she has: 17 peanuts, 9 cashews, 12 almonds, and 10 walnuts. 


Armando scoops out a bowl of 32 nuts. About how many should he expect to be cashews?

anonymous · Answer

Of the 48 total nuts, 9 are cashews, so the expected *frequency* of cashews is $\dfrac{9}{48}$. The expected *number* of cashews in the bowl of 32 would be 32 multiplied by the expected frequency.