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A large bin of mixed nuts contains peanuts, cashews, almonds, and walnuts. Sheila scoops out a bowl full of nuts and counts how many of each type she has: 17 peanuts, 9 cashews, 12 almonds, and 10 walnuts. Armando scoops out a bowl of 32 nuts. About how many should he expect to be cashews?
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Of the 48 total nuts, 9 are cashews, so the expected *frequency* of cashews is \(\dfrac{9}{48}\). The expected *number* of cashews in the bowl of 32 would be 32 multiplied by the expected frequency.
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