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Mathematics 22 Online
OpenStudy (cakecup2018):

Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share? PLEASE HELP!!!

OpenStudy (cakecup2018):

OpenStudy (anonymous):

well first find what x and y are

OpenStudy (anonymous):

how would you find y?

OpenStudy (cakecup2018):

you would find y by finding side x. 12^2+5^2

OpenStudy (anonymous):

it's easier to use tangent

OpenStudy (anonymous):

so \[\tan \theta=opp/adj\]

OpenStudy (cakecup2018):

well i found the hypotenuse by pythag

OpenStudy (anonymous):

opposite is 12, adjacent is 5

OpenStudy (anonymous):

ok, what angle did you get?

OpenStudy (cakecup2018):

would i put the leg measures over the hypotenuse

OpenStudy (cakecup2018):

?

OpenStudy (anonymous):

leg measures? I don't understand

OpenStudy (cakecup2018):

12, 5 are the legs....

OpenStudy (cakecup2018):

13 is hypotenuse

OpenStudy (anonymous):

ok, so now lets find angle y

OpenStudy (cakecup2018):

ok..

OpenStudy (cakecup2018):

sin x and cos y

OpenStudy (anonymous):

ok, so lets use cos to find y

OpenStudy (cakecup2018):

idk what to put in im confused..

OpenStudy (anonymous):

\[\cos \theta=adj/hyp\]

OpenStudy (anonymous):

adj is 5 and hyp is 13

OpenStudy (cakecup2018):

it would approx .38 degrees ?

OpenStudy (anonymous):

remember, we are trying to find theta, so \[\theta=\cos ^{-1}(5/13)\]

OpenStudy (cakecup2018):

so it would be 67.38 degrees

OpenStudy (anonymous):

that's right

OpenStudy (anonymous):

so cos(y) would be?

OpenStudy (cakecup2018):

was that for sin x?

OpenStudy (anonymous):

no we just found angle y. now take the cos of the angle to find the value of cos(y)

OpenStudy (anonymous):

cos(67.38)

OpenStudy (cakecup2018):

.384

OpenStudy (cakecup2018):

@10115658 can u lease help...

OpenStudy (anonymous):

yep, so that's the value for cosy

OpenStudy (anonymous):

now let's find angle x

OpenStudy (cakecup2018):

im confused ... sin x = 5/13 and cos y = 12/13

OpenStudy (anonymous):

no we just found cos y which was .384, now we have to find sin x.

OpenStudy (cakecup2018):

ok so would i do the inverse of sin x?

OpenStudy (anonymous):

first lets find the angle x

OpenStudy (cakecup2018):

ok how ?

OpenStudy (anonymous):

lets use cos again

OpenStudy (cakecup2018):

22.6

OpenStudy (anonymous):

so it's \[\cos \theta=adj/hyp\]

OpenStudy (anonymous):

that's right, good job

OpenStudy (anonymous):

so now find sin(22.62)

OpenStudy (cakecup2018):

so whats the relationship?

OpenStudy (cakecup2018):

.38

OpenStudy (anonymous):

yep, and what did we get for cos y?

OpenStudy (cakecup2018):

67.38

OpenStudy (cakecup2018):

no i mean...

OpenStudy (cakecup2018):

.38

OpenStudy (anonymous):

that's right, so the relationship is that they are the same value

OpenStudy (cakecup2018):

thank u sooo much i am giving u a medal !

OpenStudy (anonymous):

the ratio would be .38/.38=1

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