Question

Please check my answer(:


A right triangle has legs with lengths 7 cm and 24 cm.

What is the length of the hypotenuse?

___cm (23) ?

thanks btw <3

**no im not gay yes im a guy**

-.-

Answer 1

please help meh D:

Answer 2

what is your asnwer u need us to check?

Answer 3

mmy answer is 23

Answer 4

How'd you get 23? show us your work

Answer 5

and yep

Answer 6

ugh jeez, 24^2 - 7^2 is 527 and the square root for that is 23 (in the tenth place..rounded)

Answer 7

\[A^2+B^2 = C^2 ...............7^{2} + 23^2 = C^2\]

Answer 8

sooo.....

Answer 9

XD

Answer 10

:) Come on, i laid it out for you. 49 + 576 = c^2

Answer 11

The problem was that you messed up the formula. It's A2+B2=C2. Not A2-B2=C2.

Answer 12

331776

e.e

Answer 13

Ah...

Answer 14

idk if thats right.

Answer 15

One sec

Answer 16

\[A ^{2}+B^{2}=C^{2} \rightarrow 7^{2} + 24^{2} = C^{2} \rightarrow 49 + 576 = C^{2} \rightarrow 625 = C^{2} \] ..... Now solve for C

Answer 17

um o.o

dude im lostt.

Answer 18

im just gonna go with 23 o.o

who cares, right XD

Answer 19

just kidding XD

Answer 20

Okay. First of all, i typed 24 instead of 23. My bad. The way to solve this is to use the Pythagorean Theorem. The therom says that \[A^2 + B^2 = C^2\] .Take both legs given to the second power. This gives you \[7^2 + 24^2 = C^2\]. Now once you have the numbers plugged in, you're left with \[49 + 576 = C^2\]. From here you got: \[625 = C^2\] Finally, you solve for C. Which you take the square of to counter the power. \[\sqrt{625} = \sqrt{C^2} \] Which turns into: \[25 = C\]. Answer is 25.

Answer 21

oh my god dude, thanks I luhh you (no homo) but i luh you

Answer 22

Does that make more sense?

Answer 23

Yea no problem, just make sure you're using the right formulas. You were almost there but you stumbled at the end.

Answer 24

yeppp.