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If the distance covered in time t is given by s(t) = 4t2 + 3t, where s(t) is in meters and t is in seconds, what is the distance covered in the interval between 2 seconds and 3 seconds? @jim_thompson5910
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"the distance covered in time t is given by s(t) = 4t^2 + 3t" so the distance covered in 2 seconds is s(2) = ??? the distance covered in 3 seconds is s(3) = ??? therefore, the distance covered from 2 to 3 seconds is equal to s(3) - s(2) = ??
i got 41-22? for s(3)-s(2)
@jim_thompson5910
double check your work
you're close but not quite there
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i keep getting to 41-22? am i missing a step?? (/__\)
recheck s(3)
it's not 41
s(3)-s(2)= 23?
correct
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