Question

Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 6.

Answer 1

y = 6/22

Answer 2

@Cblount look at the file I attached

Answer 3

Your answer is incorrect

Answer 4

Just a moment..

Answer 5

It has to be 2.58, C.. the line on the graph I just made proves that.

Answer 6

Thank you

Answer 7

Yep.

Answer 8

@Cblount

Answer 9

It might take me a bit to respond to this, give me about 5 minutes, okay?

Answer 10

Take your time, please

Answer 11

When inputted into the graph generator:

#26: C

Answer 12

When inputted into a graph generator, #27: A.\[(\frac{ 1 }{ 4 })^{x+3}\]

Answer 13

Thanks so much.

Answer 14

Wait do you mean +2?

Answer 15

No problem, let me answer that last one.

Answer 16

Yes, +2..sorry

Answer 17

It's fine

Answer 18

y intercept is the y value when x = 0
for g(x), y value can be less than 6 when x = 0 whereas y intercept of j(x) is 10 which is apparently greater than other 3 functions.. so D j(x)

Answer 19

Thank you so much @Cblount I really appreciate it.

Answer 20

@Cblount last two sorry.

Answer 21

@welshfella Can you answer them?^^^^^^^

Answer 22

I'm here, sorry

Answer 23

f(x)=2
h(x)=5
g(x)=8
j(x)=0 (Never intersects Y)

So, (in order) f(x), h(x), g(x), j(x)

Answer 24

i'm not sure about that
why do you say that j(x) never intersects y-axis?

Answer 25

Highest to Lowest: j(x), g(x), h(x), f(x)

Answer 26

yes i agree

Answer 27

why did you put j(x) as the highest then?

Answer 28

Good question, I believe one of my answers were invalid, it does intersect y at 0, along with x. so the lowest would be j(x)

g(x), h(x) , f(x), j(x)

Answer 29

the question is a bit ambiguous because you can argue that there are no values for x below onefor function j as it doesn't state them. That is the domain is 1 to 3.

Answer 30

but thats not one of the options

Answer 31

It beats me @welshfella.. maybe you can help him out