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simultaneous method
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i have FOUR equation 1=C1+C2 1=C2+C4 3e=2C3+C4e e=C4e
Maybe we could manipulate those equations a bit. 1=C1+C2 1=C2+C4 Therefore, C1 + C2 = C2 + C4 and so C1 = C4
I guess you also have to solve for e?
That reduces the equations to 3 1=C1+C2 3e=2C3+C1e e=C1e
no for constants
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You mean you have to solve for C1 C2 and C3
yes
according to the equation e=C1*e That means C1 must equal 1 right?
c4 =1
and since C1 = C4 then?
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CI , C2, C3
If C1 = 1 then from this equation 1=C1+C2 C2 would equal zero
C1=0
C2=0
No C1 = 1
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C3=e
3e=2C3+C4e 2C3 = 4e C3 = 2*e
None of this used the traditional methods for solving simultaneous equations.
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