Question

MOTION question. ^_^ I need help with part II)
http://prntscr.com/6zvdr8

Answer 1

i've done part I) ---> http://prntscr.com/6zves9 :)
But whilst doing part II) i got stuck :S

Answer 2

for part II), i've gotten this far LOL
http://prntscr.com/6zvhyx

Answer 3

write it as
\[ \frac{dx}{dt} = x^2 +1 \]
and split the dx/dt
\[ dx = (x^2 +1) \ dt \\
\frac{dx}{x^2+1}= dt \]

Answer 4

yeah, i got up to t = arctanx - arctan2
But i'm not sure where to go from here

Answer 5

or rather
x= tan(t+c) where c= atan(2)

Answer 6

wait a minute... x can equal to both tan( t - c) and tan (t + c) ? where c = atan (2)?

Answer 7

no, I posted the wrong sign for c the first time

Answer 8

oh gotchyaaa :) Just checking.
Alright so it would end up being something like this?
http://prntscr.com/6zvoea

Answer 9

yes, but maybe simpler to write
x= tan(t+c) = (tan t + 2)/(1 - 2 tan t)
where tan(c)= 2

Answer 10

okay :) thank you!