Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (theopenstudyowl):
yah np
OpenStudy (theopenstudyowl):
Happy Studying!
OpenStudy (anonymous):
what about this question?
Is the simplified form of \[2\sqrt{3}+3\sqrt{3}\] rational?
A. Yes
B. No
OpenStudy (anonymous):
@theopenstudyowl ^
OpenStudy (anonymous):
No, the simplified form is \[5\sqrt{3}\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
is the simplified form of \[2\sqrt{3}\times2\sqrt{6}\] rational?
A. Yes
B. No
OpenStudy (theopenstudyowl):
no
OpenStudy (anonymous):
i trust you @theopenstudyowl :)
OpenStudy (anonymous):
No again, as the simplified form is \[12\sqrt{2}\]
OpenStudy (anonymous):
like i said i trust you @theopenstudyowl
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
simplify \[\sqrt{3}\times \sqrt{21}\]
A. \[\sqrt{24}\]
B. \[\sqrt{63}\]
C. \[3\sqrt{7}\]
D. None of the above
OpenStudy (anonymous):
The correct answer is C.
OpenStudy (anonymous):
which statement is true about the product \[\sqrt{2}\left( 5+\sqrt{8} \right)\]?
A. It is rational and equal to 7
B. It is rational and equal to 9
C. It is irrational and equal to 4 + \[\sqrt{10}\]
D. It is irrational and equal to 4 + 5\[\sqrt{2}\]
OpenStudy (anonymous):
The correct answer is D
OpenStudy (anonymous):
Anything else you want to know?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
which statement is true about the difference \[2\sqrt{7}-\sqrt{28}\]
A. It is rational and equal to -2
B. It is rational and equal to 0
C. It is irrational and equal to \[-2\sqrt{7}\]
D. It is irrational and equal to \[\sqrt{7}\]
OpenStudy (anonymous):
@damneny ^
OpenStudy (anonymous):
@theopenstudyowl help? ^
OpenStudy (anonymous):
The correct answer is B.
OpenStudy (anonymous):
thx @damneny
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Need anything else?
OpenStudy (anonymous):
If so, then tag me.
OpenStudy (anonymous):
I got 100% because of you and @theopenstudyowl thx :) :)