Question

A circle is described by the equation (x−12)2+(y−32)2=49. What are the cordinates for the center of the circle and the length of the radius?

(-12,-32), 23units

(-12,-32), 49units

(12,32), 49units

(12,32), 23units

Answer 1

equation of circle is
(x-x1)^2+(y-y1)^2=r^2
where r = radius
and centre is (x1,y1)

Answer 2

try it now and tell what you got ??

Answer 3

dud i cant lie i never did this before can you show me how to do this

Answer 4

you understood what i wrote above in the equation???

Answer 5

i think so

Answer 6

if you compare my equation with your equation what is x1 = ???

Answer 7

2x

Answer 8

x1 is what we subtracted from x

Answer 9

what you subtracted from x in your equation??

Answer 10

x

Answer 11

x-x = 0

Answer 12

(x-12)2

Answer 13

what is subtracted from x here ??

Answer 14

12

Answer 15

that is our x1
x1=12

Answer 16

if we compare we can see 12 is subtracted from x soit will be x1

Answer 17

similarly can you tell me y1=??

Answer 18

y

Answer 19

what is subtracted from y = y1

Answer 20

so y1=??

Answer 21

1

Answer 22

how ???

Answer 23

hay im runing out of time this class almost over

Answer 24

in your equation what is subtracted from the y ??

Answer 25

y1

Answer 26

(x−12)2+(y−32)2=49
i dont see y1 anywhere in this equation ..where do u find y1 in this ??

Answer 27

32

Answer 28

wow .....so y1=32

Answer 29

x1=12 and y1=32
and our centre is (x1,y1)

Answer 30

plug in the value of x1 and y1

Answer 31

so it 12,32 49 units

Answer 32

r^2=49
r=7

Answer 33

so it 23?