Question

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How can one fourthx − 3 = one halfx + 8 be set up as a system of equations?

How can one fourthx − 3 = one halfx + 8 be set up as a system of equations?

How can one fourthx − 3 = one halfx + 8 be set up as a system of equations?

How can 1/4x-3=1/2x+8 be set up as a system of equations?

Answer 1

@texaschic101
sorry it posted the question 30 thousand times lol

Answer 2

\[\frac{ 1 }{ 4 }x-3=\frac{ 1 }{ 2 }+8\]

Answer 3

@phi @mathlover2014 @mathman101

Answer 4

well.....not sure about this...you will need a second opinion

I am thinking your set of equations is :
y = 1/4x - 3
y = 1/2x + 8
and when solving, you would set it up like this..
1/4x - 3 = 1/2x + 8

Answer 5

do you want me to post the answer options?

Answer 6

oh...lol...that would help

Answer 7

alright one sec:)

Answer 8

@texaschic101

Answer 9

solve for y, then set them equal to each other
4y - x = -12
4y = x - 12
y = 1/4x - 3

2y - x = 16
2y = x + 16
y = 1/2x + 8

therefore, 1/4x - 3 = 1/2x + 8 ......answer is the 2nd one

Answer 10

thank you so much! i really appreciate it!!!

Answer 11

no problem :)