Use the image below to answer the following question. Find the value of sin x° and cos y°. What relationship do the ratios of sin x° and cos y° share?
Does the length of the hypotenuse help you find a relationship? See if you can find it WITHOUT calculating the length of the third side.
would i use AC2+CB2=AB2
You can do it!! \(\sin(x) = \dfrac{What?}{Hypotenuse}\) \(\cos(y) = \dfrac{What?}{Hypotenuse}\)
i know sin = opp/ hyp , and cos=adj/hyp
Okay, now answer my question. Don't forget to notice that the two expressions are NOT using the same angle.
sin= 8/hypotenuse cos=6/hypotenuse .....is that what your asking? Lol sorry im confused
No, you're using the SAME angle. Don't do that. Use the cosine of one of the acute angles, y. Use the sine of the other of the acute angles, x.
i figured out that the hypotenuse is 10
using the Pythagorean theorem
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