Mathematics
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OpenStudy (freemap):
What are the values of x when tan(x) is undefined?
A.-270°, -90°, 90°, and 270°
B.-270°, -90°, 0°, 90°, and 270°
C.-360°, -180°, 0°, 180°, and 360°
D.-360°, 0° and 360°
11 years ago
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OpenStudy (anonymous):
remember tan= sin/cos
11 years ago
OpenStudy (anonymous):
where does cos=0?
11 years ago
OpenStudy (freemap):
I'm sorry can you give me some background information of tan and sin and cos
11 years ago
OpenStudy (anonymous):
so tangent is the same as sin/cos
11 years ago
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OpenStudy (anonymous):
anything divided by 0 is undefined
11 years ago
OpenStudy (anonymous):
so using the unit circle, find where cos=0
11 years ago
OpenStudy (freemap):
Isn't undefined a vertical line?
11 years ago
OpenStudy (anonymous):
undefined means that nothing exists at that point
11 years ago
OpenStudy (anonymous):
So if you look at the unit circle cos is 0 at 90 degrees
11 years ago
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OpenStudy (anonymous):
can you find the other point that it equals 0?
11 years ago
OpenStudy (freemap):
270 degrees
11 years ago
OpenStudy (freemap):
Is the answer b
11 years ago
OpenStudy (anonymous):
270 is correct. What does cos equal at 0 degrees?
11 years ago
OpenStudy (freemap):
I don't know 0
11 years ago
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OpenStudy (anonymous):
no
11 years ago
OpenStudy (freemap):
270 and 90 degrees
11 years ago
OpenStudy (anonymous):
at 0 cos=1
11 years ago
OpenStudy (anonymous):
that means that cos is defined at 0
11 years ago
OpenStudy (anonymous):
so now we have our two values 90 and 270
11 years ago
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OpenStudy (anonymous):
The negative values will also produce 0 for cos
11 years ago
OpenStudy (anonymous):
So what is the answer?
11 years ago
OpenStudy (freemap):
A
11 years ago
OpenStudy (jdoe0001):
\(\bf tan(\theta)=\cfrac{sin(\theta)}{{\color{brown}{ cos(\theta) }} }\qquad if\ {\color{brown}{ cos(\theta) }}=0\ then
\\ \quad \\
tan(\theta)=\cfrac{sin(\theta)}{{\color{brown}{ 0}}}\impliedby undefined\)
as already pointed out
11 years ago
OpenStudy (anonymous):
That's right
11 years ago
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OpenStudy (freemap):
SO the answer is A
11 years ago
OpenStudy (jdoe0001):
and at 90 and 270 degrees
cosine is indeed 0
going backwards with negatives, will land on the same spots
as 10115658 said
11 years ago
OpenStudy (anonymous):
looking at the graph of tan, the lines disappear at 90, 270, -90, -270
11 years ago
OpenStudy (freemap):
Thanks so much for your time.
11 years ago
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OpenStudy (anonymous):
no problem
11 years ago