how to solve attached
first move the 8 to the left side of the equation
@10115658 you can't factor the 2 out from -x, it will become -1/2x
Not quite. You can't factor out the 2 like that.
You have to use the Quadratic formula
ya my bad
@nickymail48 here's a good visual for the Quad Formula http://www.teachingforexcellence.com/wp-content/uploads/2012/05/Math-Quadratic-Formula1.jpg
yep quad formula works
ok teacher didnt explain ir was quadratic
\(\Large 2x^2-x+8=0\) Quadratic formula: \(\Large ax^2+bx+c=0\) \(\large x=\Large\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
@nickymail48 What did you get for an answer?
\(\bf 2x^2-x=-8\implies 2x^2-x+8=0 \\ \quad \\ \textit{quadratic formula}\\ {\color{blue}{ 2}}x^2{\color{red}{ -1}}x{\color{green}{ +8}}=0 \qquad \qquad x= \cfrac{ - {\color{red}{ b}} \pm \sqrt { {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}}}{2{\color{blue}{ a}}}\)
thanks
1+-3i sqrt 7/4
Um, I think you may have typed it in wrong, but you might have it written down correctly. Do you have \[1/4 \pm (3i \sqrt{7})/4\] ?
yah ido i dont now how to write it like that
Using the blue equation button below the text box to insert an equation. But it looks like you got it right!
ok thanks!
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