Mathematics
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OpenStudy (i_love_my_nieces):
Question in commets
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OpenStudy (i_love_my_nieces):
Mehek (mehek14):
Do you have options?
OpenStudy (i_love_my_nieces):
No. It's where you have to show the formula, the work, and the answer
Mehek (mehek14):
Do you know the formula?
OpenStudy (i_love_my_nieces):
\[LA = a \sqrt{a ^{2}}+ 4 h ^{2}\]
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OpenStudy (i_love_my_nieces):
Right?
Mehek (mehek14):
Yes \(\Large{A_L = a\sqrt{a^2 + 4h^2}}\)
Mehek (mehek14):
A = base edge
H = height
OpenStudy (i_love_my_nieces):
So A = 8 and H = 22?
Mehek (mehek14):
yes
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Mehek (mehek14):
now put them into the equation
OpenStudy (i_love_my_nieces):
357
Mehek (mehek14):
yes about 357.77
OpenStudy (i_love_my_nieces):
Should I put 357 or 357.77?
Mehek (mehek14):
Does it say round to the nearest whole number?
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OpenStudy (i_love_my_nieces):
No.
Mehek (mehek14):
it doesn't matter which one you put because it's about 357.77
OpenStudy (i_love_my_nieces):
I think I will put 357.77
Mehek (mehek14):
alright \(\ddot\smile\)
OpenStudy (i_love_my_nieces):
@Mehek14 can you help me with two more please?\[:)\]
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Mehek (mehek14):
yes
OpenStudy (i_love_my_nieces):
Post here or new?
Mehek (mehek14):
doesn't matter
OpenStudy (i_love_my_nieces):
OK, here it is
OpenStudy (i_love_my_nieces):
The formula is..
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OpenStudy (i_love_my_nieces):
\[SA = \Pi r(r +\sqrt{h ^{2}+ r ^{2}}\]
Mehek (mehek14):
Your picture doesn't show the height
OpenStudy (i_love_my_nieces):
Yes it does 7 in
Mehek (mehek14):
that's the slant
Mehek (mehek14):
but if you believe it's the height then plug it in the formula
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OpenStudy (i_love_my_nieces):
Radius = 4 in, right
Mehek (mehek14):
yes
OpenStudy (i_love_my_nieces):
151.58?
Mehek (mehek14):
yes
OpenStudy (i_love_my_nieces):
Is that my answer?
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Mehek (mehek14):
yea
OpenStudy (i_love_my_nieces):
hold on and i will post the other one
OpenStudy (i_love_my_nieces):
Or is it 20.6?
Mehek (mehek14):
151.58 <---I got that as well
OpenStudy (i_love_my_nieces):
oh okay, and to get you go | \[3.14 \times 4(4 + \sqrt{7 ^{2}+ 4 ^{2}} =151.58\]
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Mehek (mehek14):
yes ik that
OpenStudy (i_love_my_nieces):
No I was just double checking
OpenStudy (i_love_my_nieces):
OpenStudy (i_love_my_nieces):
@Mehek14
OpenStudy (i_love_my_nieces):
\[V = \Pi r ^{2}h\]
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Mehek (mehek14):
\(π*17^2*27\)
OpenStudy (i_love_my_nieces):
V = 3.14 x 17^2 x 27 =2450.12
OpenStudy (i_love_my_nieces):
* 24501. 42
Mehek (mehek14):
\(\checkmark\)
OpenStudy (i_love_my_nieces):
I am right!! Yay!!
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OpenStudy (i_love_my_nieces):
1: Formula: LA = πr(r + 'square root h^2 + r^s')
Work: 8 'square root 8^2 + 4 × 22^2
Answer: 357.77 m
2: Formula: SA = πr(r + 'square root h^2 + r^2')
Work: 3.14 × 4(4 + 'sqaure root 7^2 + 4^2')
Answer: 152.58 in
3: Formula: V = πr^2h
Work: 3.14 × 17^2 × 27
Answer: 24501.42 m
Is this correct? @Mehek14
Mehek (mehek14):
yes