Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (help_people):

Help please doing this review packet.

OpenStudy (help_people):

An equation is shown below: 3 over 2 multiplied by x plus 7 over 2 equals 2 to the power of x What is the solution to the equation? x = 1 x = 3 x = 5 x = 8

OpenStudy (help_people):

@Nnesha @confluxepic

Nnesha (nnesha):

\[\huge\rm \frac{ 3 }{ 2 } \times \frac{ x+7 }{ 2 } = x^2\] like this ?

OpenStudy (help_people):

no

OpenStudy (xapproachesinfinity):

2^x not x^2

OpenStudy (help_people):

3/2x +7/2=2^x

OpenStudy (xapproachesinfinity):

other than that she is correct

OpenStudy (xapproachesinfinity):

according to what you wrote it should be what @Nnesha wrote but the right hand side should have been 2^x

OpenStudy (help_people):

no she is wrong this is what it is suppose to be

OpenStudy (xapproachesinfinity):

that's what you wrote in words

Nnesha (nnesha):

;-;

OpenStudy (help_people):

\[3/2x +7/2=2^x\]

OpenStudy (xapproachesinfinity):

you should have been procise

Nnesha (nnesha):

aww that's fine :-)

OpenStudy (help_people):

i did i typed it in for you

Nnesha (nnesha):

okay thanks :-)

OpenStudy (xapproachesinfinity):

oh didn't see it sorry :)

OpenStudy (xapproachesinfinity):

what did you do so far

Nnesha (nnesha):

http://prntscr.com/70ocfk for fraction

Nnesha (nnesha):

\[\huge\rm \frac{ 3 }{ 2x } + \frac{ 7 }{ 2 } =2^x\]

OpenStudy (xapproachesinfinity):

i would first do \[2(\frac{3}{2x}+\frac{7}{2})=2^{x+1} \]

OpenStudy (help_people):

so which one do i di ? @Nnesha

OpenStudy (xapproachesinfinity):

hmm i think you just do direct subtitution of the given solutions to get the right

OpenStudy (xapproachesinfinity):

replace x=1 and see if it work and so on

OpenStudy (xapproachesinfinity):

x=1 is not a solution since \[5\ne2\]

Nnesha (nnesha):

hmm find common denominator (left side )

OpenStudy (xapproachesinfinity):

do x=3 \[4\ne8\]

OpenStudy (xapproachesinfinity):

your given solutions are not correct thus far!

OpenStudy (help_people):

x=5 is not either

OpenStudy (xapproachesinfinity):

all of your solution are not good do you have other option here or the equation you did is incorrectly written

OpenStudy (xapproachesinfinity):

logically 2^x for x>0 is always larger than the left hand side

OpenStudy (help_people):

no my equation is correct: 3/2x+7/2=2^x

OpenStudy (help_people):

@Nnesha what do you think?

OpenStudy (xapproachesinfinity):

no you didn't write it correctly i should have been\[\frac{3}{2}x+\frac{7}{2}=2^x\] \[3x+7=2^{x+1}\] plug in 3 \[16=16\]

OpenStudy (xapproachesinfinity):

next time be careful what you write and be precise!

OpenStudy (xapproachesinfinity):

YOU SHOULD HAVE WRITTEN (3/2)X TO TELL US THAT X IS NOT IN DENOMINATOR

Nnesha (nnesha):

O_O

OpenStudy (help_people):

srry geesh

OpenStudy (help_people):

and i did tell you like 50 times

OpenStudy (xapproachesinfinity):

hahah @Nnesha i was suspicious of the equation from the start lol it didn't make sense as i said above the right side is extremely larger than the left

Nnesha (nnesha):

\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm \frac{ 3 }{ 2x } + \frac{ 7 }{ 2 } =2^x\] \(\color{blue}{\text{End of Quote}}\) do you know why i typed that ? you should tell us x is not in denominator

OpenStudy (xapproachesinfinity):

you didn't tell us anything we wrote incorrectly and you didn't say no x shouldn't be in denominator hahah so we thought that's how you the equation is

OpenStudy (help_people):

i told you it was wrong and tyoed the right thing like 10 times

OpenStudy (help_people):

go up and look please do

OpenStudy (xapproachesinfinity):

you typed the wrong one my dear 3/2x x for us is in denominator here you should use parenthesis

Nnesha (nnesha):

ahh okay i should wear my glasses nd dunno abt u xapprochesinfinity

OpenStudy (help_people):

see may you help with a few more i have a review packet for this test and i am trying to understand this stuff @nnesha i will open up another page

OpenStudy (xapproachesinfinity):

heheh for me i don't see anywhere where you said x should not be in the bottom

OpenStudy (xapproachesinfinity):

good luck

OpenStudy (xapproachesinfinity):

have you wonder why i plugged in 3 directly?

Nnesha (nnesha):

educated guess o^_^o1

OpenStudy (help_people):

yeah well isn't it because you are trying to find the answer by plugging in numbers so that was the first one you wanted to do :D

OpenStudy (xapproachesinfinity):

hmmmm well that could be part of the reasoning however, another reason is that we can't solve that equation with elementary methods that you learned thus far. you will need a lot of other tools to be able to tackle that equation

OpenStudy (xapproachesinfinity):

here all that concerned us was an integer solution so direct sub is useful :)

OpenStudy (help_people):

ok thanks do you mind helping me w. another @xapproachesinfinity

OpenStudy (xapproachesinfinity):

let's see :)

OpenStudy (xapproachesinfinity):

repost that is

OpenStudy (help_people):

ok

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!