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OpenStudy (anonymous):
ILL GIVE YOU A MEDAL AND FAN!!!
Write log3 6 as a logarithm of base 2.
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OpenStudy (welshfella):
use the change of base formula for logs
OpenStudy (anonymous):
I dont know what that is.
OpenStudy (anonymous):
@texaschic101
Nnesha (nnesha):
change of base formula
\[\huge\rm log_a b = \frac{ \log b }{ \log a }\]
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Nnesha (nnesha):
\[\log = \log_{10}\]
OpenStudy (anonymous):
Im just kind of confused as to how I'm supposed to plug it in.. if that makes sense
OpenStudy (welshfella):
log2 6 = log3 6
-----
log3 2
OpenStudy (welshfella):
you can find log3 2 as a decimal y then
log3 6 = y log2 6 = log2 6^y
OpenStudy (welshfella):
to find log3 2:-
2 = 3^y
ln2 = y ln3
y = ln 2 / ln 3 = 0.6309
giving log3 6 = log2 6^(0.6309) = log2 3.097
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OpenStudy (anonymous):
is that the answer?
OpenStudy (welshfella):
yes
OpenStudy (anonymous):
could you write it out as an equation? thats not one of the options...
OpenStudy (welshfella):
log3 6 = log2 6 / log2 3
OpenStudy (anonymous):
could you help me with this last one?
Write log8 3 as a logarithm of base 5.
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OpenStudy (welshfella):
iys very similar to the last one
log8 3 = log5 3 / log5 8
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