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What is the y-value for f(x) = tan(x) when x = -45°?
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replace x by -45
remember: \[\huge\rm \tan = \frac{ \sin }{ \cos }\]
Have you tried inputting tan(-45) into a calcualtor?
\(\bf tan(-45^o)=\cfrac{sin(-45^o)}{cos(-45^o)}\qquad \begin{cases} sin(-\theta)=-sin(\theta)\\ cos(-\theta)=cos(\theta) \end{cases} \\ \quad \\ \cfrac{sin(-45^o)}{cos(-45^o)}\implies \cfrac{-sin(45^o)}{cos(45^o)}\implies -\cfrac{sin(45^o)}{cos(45^o)}\implies -tan(45^o)\) check your Unit Circle, or as suggested already, use your calculator
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