If sin0= 12 over 13 and cos0 < 0, what is tan0 ? Will give medal
sin = ? opposite hypotenuse adjacent ?
guess that 0 is a \(\theta\) right?
Yes the whole problem didn't post
http://openstudy.com/study#/updates/55447da0e4b0629c5c698484 if you don't know tutorial |dw:1430616774574:dw|
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find the third side via pythagoras or from memory then the tangent is opposite over adjacent, although it is negative in this case
@satellite73 do I add the sides
oh no!
\[a^2+12^2=13^2\\ a^2=13^2-12^2\] solve that for \(a\)
let me know when you get \(a^2=25\) so \(a=5\)
I just did it I got 25 also
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tangent is opposite over adjacent make sure you put a minus sing in front, since you are told cosine is negative
Thanks for the help @satellite73 :)
lol yw
so \[\huge\rm cos \theta <0 \] it can be in 3rd quadrant ???
|dw:1430618052289:dw| remember \(\huge\color{green}{{\rm CAST}}\) rule!
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